coding

[Prabin garhwal]

Hello!.. m trying to implement a code to transform any matrix to row reduced echelon form.. i have done some coding over it bt still canoot get the output correctly… can u please help me through it…here is how i have done..

#include<stdio.h>

#include<math.h>

main()

{

int orgp[20][20],dupp[20][20];

int rc,cc,i,j,r,lead=0,c;

int z,a,b;

 

printf("Enter row size::n");

scanf("%d",&rc);

printf("Enter column size ::n");

scanf("%d",&cc);

printf("Enter the parity check matrix row wise :: n");

for(i=0;i<rc;i++)

{

for(j=0;j<cc;j++)

{

scanf("%d",&orgp[j]);

dupp[j]=orgp[j];

}

}

printf("Enter matrix is :: n");

for(i=0;i<rc;i++)

{

        for(j=0;j<cc;j++)

        {

        printf("%d",orgp[j]);

        printf("t");

        }

printf("n");

}

 

for(r=0;r<rc;r++)

{

if(cc<=lead)

{

break;

}

i=r;

while(orgp[lead]==0)

{

i=i+1;

if(rc==1)

{

i=r;

lead=lead+1;

if(cc=lead)

{

break;

}

}

}

 

 

a=i;

b=r;

for(i=0;i<rc;i++)

{

c=orgp[a-1];

orgp[a-1]=dupp[b-1];

dupp[b-1]=c;

 

}

 

if(orgp[r][lead]!=0)

{

z=orgp[r][lead];

for(j=0;j<cc;j++)

{

orgp[r][j]=orgp[r][j]/z;

}

}

 

for(i=0;i<rc;i++)

{

if(i!=r)

{

for(j=0;j<cc;j++)

{

orgp[j]=orgp[j]-orgp[lead]*orgp[r][j];

}

}

 

}

lead=lead+1;

}

 

printf("The matrix in reduced echelon form is ::n");

for(i=0;i<rc;i++)

{

        for(j=0;j<cc;j++)

        {

        printf("%d",orgp[j]);

        printf("t");

        }

        printf("n");

}

 

 

 

 

}

 

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