7 segment with 8051 using interrupt

This topic has 1 reply, 2 voices, and was last updated 11 years, 5 months ago by Ashutosh Bhatt.

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February 17, 2014 at 2:43 pm #2870

Amit Raijade
Participant

i want to display set-01 on seven segment display using interrupt

i have attached code for it

but not working well

#include <reg51.h>

#define PORT_SEVEN_SEG P0

#define blank 0x00

sbit dig0 = P2^1;

sbit dig1 = P2^2;

sbit dig2 = P2^3;

sbit dig3 = P2^4;

sbit dig4 = P2^5;

sbit dig5 = P2^6;

unsigned char data display_arr[6], bcdval[6], dig_count, l_display_arr[6];

//void pin_status();

void initialize();

/*

void delay(unsigned int ms)

{

int i, j;

for(i=0;i<ms;i++)

for(j=0;j<300;j++);

}

*/

void main()

{

int i,j=0;

code unsigned char Setup1[] = {0x15,0x91,0xD1,0xFD,0x03,0x6F}; //set-1

initialize();

EX0 = 1;

for(i = 0; i < 6;i++){

display_arr = Setup1;

//delay(1);

}

EX0 = 0;

}

void initialize()

{

P0 = blank; //segments off

P2 = 0xfe; //digits off

//P1 = 0xff;

TMOD = 0x00; //gate1, c/t1, m1, m0, gate0, c/t0, m1, m0

// 0   0 1 0, 0 0 0 1 timer1 8 bit, timer0 16 bit;

TCON = 0x11; //timer1 flag, timer1 on,

//timer0 flag, timer0 0n,

//ext int1 flag, ext int1 edge/low-(1/0), ext int0 flag, ext int0 edge/low-(1/0)

PCON = 0x00; //smod, res, res, res,

//gf1, gf0, pd, idl

SCON = 0x40; //sm0, sm1, sm2 (mode 01 8 bit var baud),

//recv_enb ,tb8,rb8,ti,ri

IE = 0x82; //enable all, res, enable timer2, enable serial,

//enable timer1 , enable extint1, enable timer0, enable extint0

TH1 = 0xfA; //f4_2400, fd_9600, fa_4800, e8_1200

TL1 = 0xfA;

TH0 = 0x78;

TL0 = 0x00;

//TR0 = 1;

}

void timer0() interrupt 1

{

TH0 = 0x78;

TL0 = 0x00;

P0 = 0xff;

if(dig_count == 6)

dig_count = 0;

switch(dig_count)

{

case 0: dig0 = 0;

         dig1 = 1;

   dig2 = 1;

dig3 = 1;

dig4 = 1;

dig5 = 1;

break;

case 1: dig0 = 1;

dig1 = 0;

dig2 = 1;

dig3 = 1;

dig4 = 1;

dig5 = 1;

break;

case 2: dig0 = 1;

dig1 = 1;

dig2 = 0;

dig3 = 1;

dig4 = 1;

dig5 = 1;

break;

case 3: dig0 = 1;

dig1 = 1;

dig2 = 1;

dig3 = 0;

dig4 = 1;

dig5 = 1;

break;

case 4: dig0 = 1;

dig1 = 1;

dig2 = 1;

dig3 = 1;

dig4 = 0;

dig5 = 1;

break;

case 5: dig0 = 1;

dig1 = 1;

dig2 = 1;

dig3 = 1;

dig4 = 1;

dig5 = 0;

   break;

}

P0 = display_arr[dig_count];

TF0 = 0;

dig_count++;

}

void int1() interrupt 2

{ }

void timer1() interrupt 3

{ }

void rec() interrupt 4

{ }

February 19, 2014 at 4:52 am #11056

Ashutosh Bhatt
Participant

you have not specified which interrupt you want to use

in your program you are enabling external interrupt 0 but your ISR is for timer 0 interrupt (interrupt 1 keyword is for timer 0 interrupt)

also you have not enabled globle interrupt

use IE = 0x81 to enable external interrupt 0

and IE = 0x82 to enable timer 0 overflow interrupt
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