You are here: Home
If your battery comprises of 3 cells…. follow below caluculation….
6v 5Ah Lead Sulphuric Acid Batteries
Nominal Capacity 77oF(25oC)
20 hour rate (0.25A, 5.25V) 5Ah
10 hour rate (0.47A, 5.25V) 4.7Ah
5 hour rate (0.78A, 5.25V) 3.9Ah
1 hour rate (3.2A, 4.8V) 3.2Ah
6v 4.5Ah Lead Sul
Nominal Capacity 77oF(25oC)
20 hours rate(0.225A 5.25V)4.5Ah
10 hours rate(0.43A 5.25V)4.3Ah
5 hours rate(0.78A 5.25V)3.9Ah
1 hour rate(2.8A 4.8V) 2.8Ah
You Might Find the help from schematic given below
Standard Second Order Equation for Step Input
I have taken Step Input because G(s)=a/(s0)(s+a)
comparing above two equations…
Time Constant (T)= (1/ ??n)
?n= ?a rad/sec.
2??n= 1 or
?= 1/2(?a)
so Time Constant(T)=0.5
Current Transformers Turns Ration=Secondary Current/Primary current
so you were asking to find ct ratio…. Here Primary Current for CT Will be 628.29A but there is no way to find CT Ratio without knowing Secondary Current of CT
Insufficient Data