T89C51AC2 10bit ADC

[David]

Dear people,

 

I have succesfully programmed a T89C51AC2 microcontroller into using its in-built ADC in 8-bit mode. However I would like to operate this in-built ADC in 10-bit mode. Below please find the code for an 8-bit mode operation:

 

<code>

#include <T89C51AC2.h> //T89C51AC2 Library

 

unsigned char PAN_DAT[5];   //Array containing 5 spaces

unsigned int value_converted;

 

void main(void)

{

unsigned int value;

 

ADCF=0x07;     //Set P1.0, P1.1, P1.2 as ADC 

ADCON=0x20; //Enable ADC function

ADCLK=0x00; //Pre-Sacler Time=0us

 

value = ADC(0xF9,0x01);                        //Initialize ADC for pin 1 of P1 using mask

 

PAN_DAT[0] = (value/100)|0x30;           //Extract ‘units’ value and convert to ASCII

PAN_DAT[1] = (‘.’);                                //Separate ‘units’ from ‘tenths’ with ‘.’

PAN_DAT[2] = ((value%100)/10)|0x30; //Extract ‘tenths’ value and convert to ASCII

PAN_DAT[3] = (value%10)|0x30;           //Extract ‘hundredths’ value and convert to ASCII

}

 

unsigned char ADC(unsigned char channel,mask)

{

unsigned int value;                          //Integer space declaration ‘value’

 

ADCON=ADCON&channel;      //select ADC pin using ADC control

ADCON=ADCON|mask;           //Mask for I/O pin

ADCON=ADCON|0x08;           //Start ADC conversion in 8-bit (ADSST=1)

while((ADCON&0x10)!=0x10); //Wait ADEOC=1 bit4

value=ADDH;                             //Save result in ‘value’

ADCON=ADCON&0xEF;        //Clear ADEOC (flag=0)

return(value);                                //Return ‘value’ to main

}</code>

 

Now I know that in order to use the 10-bit mode operation an interrupt must be used. Currently I have arrived here in programming:

 

<code>

 

#include <T89C51AC2.h> //T89C51AC2 Library

 

unsigned char PAN_DAT[5];    //Array containing 5 spaces

unsigned int value_converted;

bit EOC = 0; //End-of-Conversion Flag

 

void main(void)

{

unsigned int value;

 

ADCF=0x07;      //Set P1.0, P1.1, P1.2 as ADC 

ADCON=0x20;  //Enable ADC function

ADCLK=0x00;  //Pre-Sacler Time=0us

EA = 1;              //Enable Interrupts

EADC = 1;         //Enable ADC Interrupt

 

value = ADC(0xF9,0x01);                        //Initialize ADC for pin 1 of P1 using mask

 

PAN_DAT[0] = (value/100)|0x30;           //Extract ‘units’ value and convert to ASCII

PAN_DAT[1] = (‘.’);                                //Separate ‘units’ from ‘tenths’ with ‘.’

PAN_DAT[2] = ((value%100)/10)|0x30;  //Extract ‘tenths’ value and convert to ASCII

PAN_DAT[3] = (value%10)|0x30;           //Extract ‘hundredths’ value and convert to ASCII

}

 

 

unsigned char ADC(unsigned char channel,mask)

{

unsigned int value;                    //Integer space declaration ‘value’

 

ADCON=ADCON&channel;  //select ADC pin using ADC control

ADCON=ADCON|mask;        //Mask for I/O pin

ADCON=ADCON|0x48;       //Start ADC conversion in 10-bit (ADSST=1, PSIDLE = 1)

while(!EOC);                            //Wait end-of-conversion

EOC = 0;                                  //Clear software flag

value = value_converted;

return(value);                            //Return ‘value’ to main

}

 

void IT_ADC(void)                              //ADC Interrupt

{

ADCON=ADCON&0xEF;               //Clear ADEOC (flag=0)

value_converted = ADDH<<2;          //Save first 8-bits in ‘value_converted’

value_converted |= (ADDL & 0x03);  //Save last 2-bit in ‘value_converted’

EOC = 1;                                            //Set end-of-conversion flag

}

 

</code>

 

Can someone please identify where the problem is?

 

Regarding the ADC interrupt ‘IT_ADC’ I know that it should be called in order for the program to execute it but I do not know where to call it and also, when I read the datasheet it said that: 

 

“An interrupt end-of-conversion will occurs when the bit ADEOC is actived and the bit EADC is set. For re-arming the interrupt the bit ADEOC must be cleared by software.”

[GANEEV SINGH]

Hi David

Interrupt Service Routines (ISR) are never called by us, we just define them; I mean these are interrupts and they can occur anytime during the code. They are generally triggered automatically either by internal functioning (software interrupts) or maybe due to some outside hardware changes (external interrupts).

Most of the interrupts need a corresponding flag bit to be set (logic1) in order to jump over to their ISR and all this happens automatically, we can either just monitor these flag bits (which is termed as polling technique) or set up an ISR in order to execute a funtion on its own whenever interrupt occurs.

Remember, the global interrupt enable bit should be set too to make all this happen.

[Author]

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