LCD BASIC

[Shiv Kumar Mishra]

I have a doubt in LCD code. i know, its silly question for u people but it makes big difference for me. Please 1st go through the code and at the end my questions are: 

 

void lcdcmd(unsigned char item)  //Function to send command to LCD

{

dataport = item;

rs= 0;

rw=0;

e=1;

delay(1);

e=0;

}

 

void lcddata(unsigned char item)  //Function to send data to LCD

{

dataport = item;

rs= 1;

rw=0;

e=1;

delay(1);

e=0;

}

 

void main()

{

lcdcmd(0x38); 

lcddata('A');

}

 

1. Inside the main() when we call function " lcdcmd(0x38); , the control goes on function defintion.

the function is:

void lcdcmd(unsigned char item) ;

how char datatype accept hex value i.e. 0x38 as a argument and now the arguments pass to the dataport

dataport=item; // what does this line means. It is necessary to give the command to the data port. 

 

Thanks in Advance !!!

 

[Ashutosh Bhatt]

dataport is a symbole created using #define

it does not mean it will accept only data. its a hardware port of 8051

in embedded C for 8051 the data must of 8 bit

and unsigned char is only 8 bit data. that's why we are using unsigned char

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