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You are here: Home / Topics / can i replace AT28c17 with CAT28c65B e2prom in my project?

can i replace AT28c17 with CAT28c65B e2prom in my project?

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Microcontroller › AVR › can i replace AT28c17 with CAT28c65B e2prom in my project?

  • This topic has 3 replies, 2 voices, and was last updated 12 years, 3 months ago by AJISH ALFRED.
Viewing 4 posts - 1 through 4 (of 4 total)
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    Posts
  • July 3, 2013 at 8:15 am #2520
    sai
    Participant

    AT28c17 is 16k e2prom .

     

    CAT28c65B is 64K bit e2prom.

     

    AT28c17 and CAT28c65B  are  32 pin pllc package.it has 10 adresss lines

     

    the only diffence b/w  AT28c17 and CAT28c65B  are address lines,AT28c17 has (A0-A10 adress lines) and CAT28c65B   has (A0-A12 adress lines)?

     

    the pin configrations of both  are same but

    the pins 3 and 27 are NC in AT28c17.

    the pins 3 and 27 are A12(adress 12 pin) and A11(adress 12 pin) in CAT28c65B .

    only these pins are differ.

     

    i can replace the AT28c17 by CAT28c65B in my project?without changing my software?

    does it works?

    July 4, 2013 at 4:58 am #10091
    AJISH ALFRED
    Participant

    Hi,

    I guess it will work. All you have to do is to set the same address with the address pins of the EEPROM as it is in your code.

    July 4, 2013 at 5:24 am #10093
    sai
    Participant

    Hi,

     

    i dont have source code,i cant edit in source code.

     

    In my company they were using AT28c17 ,but now this type is not available in market,so AT28c17  can be replaced by CAT28c65B (this is available in market).

     

    i want to change in my hardware?or it works by replacing ?

     

    its urgent?

     

    July 26, 2013 at 4:40 am #10205
    AJISH ALFRED
    Participant

    Hi Sai,

    You have to configure the address pins in your hardware in such a way that they matches with the adrtess used in the code. If you can edit the code properly there won’t be any hardware changes required.

    Sugest you to get the code somehow and go through it thoroughly. 

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